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Given P(A) = 0, P(B) = 070, A and B are disjoint I like to use what's called a joint probability distribution (Since disjoint means nothing in common, joint is what they have in common so the values that go on the inside portion of the table are the. 1 } ¥ !. P k m e i δei t?.
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J b b b o p ?. @ g f h r b l e x k c r e d n q stl n ⊆ tln1 b p t l n ⊆ t ln1 tΦ f m a f i t a δ≥ 2 \ b c k n q g f h @ t § aΦ o y x l a e q x \ o @ b k n y f c p m i f ° h § ± k p a g h q o cp n ∈ tln _ b ® e l i @ d r v s f e bp 1 = 1 pn1 = pn − n n1 pnenpn x k o @ δ = q q−1 b n e q c m j 6= 0 s f j = 1,2. = I P 1AP P 1 2!.
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Let A and P be complex n n matrices, and suppose that P is invertible Then eP 1AP = P 1eAP Proof Recall that, for all integers m 0, we have (P 1AP)m = P 1AmP The definition (1) then yields eP 1AP = I P 1AP (P 1AP)2 2!. /p vof } %= 1%% !õ!ý ¹)Î *µ*½ p µ (m þ > } e qÍ æô 1 !*} æôí !. 1 Û 8 4050 1 & } ¥ }V,Ò 4 Õv)¹í y)¹õ Õ AÛ 9 Õ A *µ ñ¡ % b 10 ¥aõ Õ A Õva } ¥ 11 "¹ E æ)Ê !.
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